Liquids A and B are at 30 °C and 20°C, respectively. When mixed in equal masses, the temperature of the mixture is found to be 26°C, The specific heats of A and B are in the ratio of m : n, where m and n are integers, then find minimum value of m + n.
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5
At thermal equilibrium
heat rejected by one liquid = heat accepted by other liquid
ms A (30-26) = ms B (26-20)
4s A = 6s B
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